027-remove-element
Question
https://leetcode.com/problems/remove-element/description/
Given an array and a value, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given nums = [3,2,2,3], val = 3,
Your function should return length = 2, with the first two elements of nums being 2.
Thought Process
- Since we have to move non-targeted value to the front and target value to the back, we need two pointers.
- One pointer track the location of non-targeted value from forward. T
- The other points to the location of at the end where we can insert the target value.
- Time complexity O(n)
- Space complexity O(1)
Solution
class Solution {
public int removeElement(int[] nums, int val) {
int id = 0;
for (int i = 0; i < nums.length; i++) {
if (nums[i] != val) {
nums[id++] = nums[i];
}
}
return id;
}
}