027-remove-element

Question

https://leetcode.com/problems/remove-element/description/

Given an array and a value, remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

Thought Process

  1. Since we have to move non-targeted value to the front and target value to the back, we need two pointers.
  2. One pointer track the location of non-targeted value from forward. T
  3. The other points to the location of at the end where we can insert the target value.
  4. Time complexity O(n)
  5. Space complexity O(1)

Solution

class Solution {
    public int removeElement(int[] nums, int val) {
        int id = 0;
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] != val) {
                nums[id++] = nums[i];
            }
        }
        return id;
    }
}

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