274-h-index
Question
https://leetcode.com/problems/h-index/description/
Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than hcitations each."
Example:
Given citations = [3, 0, 6, 1, 5],
which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively.
Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations
each, his h-index is 3.
Thought Process
- Sort
- If we sort citations in descending order and every index is a potential h-index
- As long we can make sure the citation is greater than its index, there are index on its left that satisfy the same requirement
- Because int array cannot take collections comparator, we can do it in reverse
- Time complexity O(n logn)
- Space complexity O(1)
- Bucket Sort
- Store the respective count in each potential h-index bucket
Solution
class Solution {
public int hIndex(int[] citations) {
Arrays.sort(citations);
int n = citations.length, i = n - 1;
while (i >= 0 && citations[i] >= n - i) i--;
return n - i - 1;
}
}
class Solution {
public int hIndex(int[] citations) {
int n = citations.length;
int[] buckets = new int[n + 1];
for (int cite : citations) {
buckets[Math.min(cite, n)]++;
}
int total = 0;
for (int h = n; h >= 0; h--) {
total += buckets[h];
if (total >= h) return h;
}
return 0;
}
}